The Function Grapher can help you Enter the equation as "y= (some function of x)" You can use zoom to find important points If you can't write the equation as "y= (some function of x)", you can try the Equation Grapher, where you enter equations like "x^2y^2=9" (meaning x2y2=9 ) But remember they are just a help! To calculate the volume of a cylinder, then, we simply multiply the area of the crosssection by the height of the cylinder V = A ⋅ h In the case of a right circular cylinder (soup can), this becomes V = πr2h Figure 621 Each crosssection ofGiven y = x 2 4x – 5 Find the following yintercept xintercepts or the zeros of the functions or roots graph of the function, given vertex is at (2, 9) Solve the system of linear equations – x 6y = 8 2x 5y = 3 Write the names of curves, given their equations x 2 /16 y 2 /9 = 1 3y = 2x 5

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Y=x^2-4x-5-Symmetryy=x^{2}4x5 he Related Symbolab blog posts Practice Makes Perfect Learning math takes practice, lots of practice Just like running, it takes practice and dedication If you wantQuestion vertex standard form?




Example 30 Differentiate Root X 3 X 2 4 3x 2 4x 5
Precalculus Find the Vertex y=x^24x5 y = x2 − 4x − 5 y = x 2 4 x 5 Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 4 x − 5 x 2 4 x 5 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = − 4, c = − 5 a = 1, bGraph a parabola by finding the vertex and using the line of symmetry and the yinterceptTo solve the equation, factor x^ {2}4x5 using formula x^ {2}\left (ab\right)xab=\left (xa\right)\left (xb\right) To find a and b, set up a system to be solved Since ab is negative, a and b have the opposite signs Since ab is negative, the negative number has greater absolute value than the positive
Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}4xy5=0 x 2 4 x − y − 5 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, and 5y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a}Whereas to graph the following equation y equals 5x squared minus x plus 15 so let me get my little scratch pad out so it's y is equal to 5x squared minus x plus 15 now there's many ways to graph this you can just take three values for X and figure out what the corresponding values for Y are just graph those three points and three points actually will determine a parabola but I want to
The standard form of a quadratic function is # y = ax^2 bx c# The function # y = x^2 4x 5" is in this form "# and by comparison a = 1 , b = 4 and c = 5 The vertex form of the equation is # y = a(x h )^2 k# where (h , k ) are the coords of the vertexGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Symmetryy=x^{2}4x5 zs Related Symbolab blog posts Practice Makes Perfect Learning math takes practice, lots of practice Just like running, it takes practice and dedication If you want




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y=x^24x5 I need to find the yintercept and x intercept and the vertex FollowAlgebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Alan P vertex at #(2,9)# Explanation Often the simplest way to do this is to convert the given equation into "vertex form" #color(whiteCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history Determine the area to the left of g(y) =2 4y−y2 g ( y) = 2 4 y − y 2 and to the right of the line x = −1 x = − 1 For problems 9 – 26 determine the area of the region bounded by the given set of curves y = x3 2 y = x 3 2, y




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Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyGraph y=x^24x5 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for Tap for more steps Use the form , to find the values of , , and Consider the vertex form of a parabola3 Graph th function using the equation in part a, explain why it is not necessary to plot points to graph when using y=a(xh)^k?



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👉 Learn how to graph quadratic equations by completeing the square A quadratic equation is an equation of the form y = ax^2 bx c, where a, b and c are c The desired figure is bounded from above by the straight line y = 5, and from below by the parabola y = x ^ 24x 5, then (5 – x ^ 2 4x 5) dx = ( x ^ 2 4x) dx = x ^ 3/3 2x ^ 2 Since the boundaries are equal to x = 0, x = 4, respectively, we substitute only the upper limit, because the lower one gives zero, into the resultingAlgebra Graph y=x^24x5 y = x2 4x − 5 y = x 2 4 x 5 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 4 x − 5 x 2 4 x 5



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Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!More » x^24x5=0 x2 4x 5 = 0 {x}^ {2}4x5=0 Restricted Access We may pursue legal actions over unauthorized uses of this APIClick here👆to get an answer to your question ️ At what points on the curve y = x^2 4x 5 is the tangent perpendicular to the line 2y x = 7 ?




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Example 30 Differentiate Root X 3 X 2 4 3x 2 4x 5
Y= \(\sqrt{x^22x5}\) Tìm giá trị nhỏ nhất của hàm số giúp mình nhé !Algebra Find the X and Y Intercepts y=x^24x5 y = x2 4x − 5 y = x 2 4 x 5 Find the xintercepts Tap for more steps To find the xintercept (s), substitute in 0 0 for y y and solve for x x 0 = x 2 4 x − 5 0 = x 2 4 x 5 Solve the equationStep by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method y=x2;y=4x5 Tiger Algebra Solver




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1 y=x^24x5 ?put this function in the form y=a(xh)k 2 What is the line of symmetry?The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}8xy1=0 x 2 8 x − y − 1 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 8 for b, and 1y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} The function y = x^2 4x 5 approximates the height, y, of a bird, and its horizontal distance, x, as it flies from one fence post to another All distances are in feet Complete the square to find and interpret the extreme value




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This video tutorial shows how to take the quadratic equation y = x^2 4x 5 and turn it into vertex form from algebra It then goes on to show graphing quaY=x^24x5 y=(x^24x4)45 y=(x2)^29 This is an equation of a parabola that opens upward Its standard (vertex) formy=(xh)^2k, (h,k)=(x,y) coordinates of the vertex vertex (2,9) axis of symmetry x=2 see graph below as a visual check What is the axis of symmetry of y=x^24x5 2 See answers madonna31 madonna31 X= 2 is the axis of symmetry JaceOTerence JaceOTerence The other answer is correct, 2 is the axis of symmetry New questions in Mathematics Need help with these 2 questions ASAP, no links and a answer with an explanation will get brainly




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The equation is now solved x^ {2}4x4=y Swap sides so that all variable terms are on the left hand side \left (x2\right)^ {2}=y Factor x^ {2}4x4 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2}Find the Vertex Form y=x^24x5 y = x2 4x − 5 y = x 2 4 x 5 Complete the square for x2 4x−5 x 2 4 x 5 Tap for more steps Use the form a x 2 b x c a x 2 b x c, to find the values of a a, b b, and c c a = 1, b = 4, c = − 5 a = 1, b = 4, c = 5 Consider the vertex form of a parabola a ( x d) 2 e a ( x d) 2 e(5,0) Given y=x^24x5 To find the xintercept, put y = 0 Then x^24x5=0 x^2x5x5=0 x(x1)5(x1)=0 (x1)(x5)=0 x1=0 x=1 x intercept (1




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Free function shift calculator find phase and vertical shift of periodic functions stepbystep31 Find the Vertex of y = x 24x5 Parabolas have a highest or a lowest point called the Vertex Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero)I have an equation right here it's a second degree equation it's a quadratic and I know it's graph is going to be a parabola this was a review that means it looks something like this or it looks something like that because the coefficient on the x squared term here is positive and it's going to be an upwardopening parabola and I am curious about the vertex of this parabola and if I have




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The only such pair is the system solution Rewrite x^ {2}4x5 as \left (x^ {2}x\right)\left (5x5\right) Rewrite x 2 4 x − 5 as ( x 2 − x) ( 5 x − 5) Factor out x in the first and 5 in the second group Factor out x in the first and 5 in the second group Factor out common term x1 by using distributive propertyVolume y=x1, y=0, x=0, x=2 \square! What is the vertex of #y=x^24x 5#?




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Y = x 2 4x 5 complete the square y 4 = (x 2 4x 5) 4 y = (x 2 4x 4) 5 4 y = (x 2) 2 1 In this form we see that the graph can be obtained by translating the graph y = x 2 right 2 units because of the x 2, and up 1 units because of the 1 y = x 2 4x 5 Reflections (x, y) is the reflection of (x, y) about yaxisThe yintercept is (0,5) When the curve intercepts the xaxis, y= 0 => x^2 4x 5 = 0 Here we see that (4)^2 < 4*a*c, the curve does not intersect the xaxis



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