√無料でダウンロード！ (x y)^2 dx (2xy x^2-1)dy=0 y(1)=1 218153-X + y 2 dx + 2xy + x 2 − 1 dy 0 y 1 1

Solve ( x 2 − y 2) d x 2 x y d y = 0 I'm asked to solve it using 2 different methods I proved I can find integrating factors of type μ 1 ( x) and μ 2 ( y / x) If I'm not wrong, these two integrating factors are μ 1 ( x) = x − 2 , μ 2 ( y / x) = ( 1 y 2 x 2) − 2 ∂ ψ ∂ x = x − 2 (

X + y 2 dx + 2xy + x 2 − 1 dy 0 y 1 1- Ex 95, 4 show that the given differential equation is homogeneous and solve each of them ( ^2 ^2 ) 2 =0 Step 1 Find / ( ^2 ^2 ) 2 =0 2xy dy = ( ^2 ^2 ) dx 2xy dy = ( ^2 ^2 ) dx / = ( ^2 ^2)/2 Step 2 Putting F (x, y) = / and finding F ( x, y) F (x, y) = ( ^2 ^2)/2 F ( x, y) = ( ( )^2 ( )^2)/ (2 )= ( ^2 ^2 ^2 ^2)/ ( ^22 )= ( ^2 ( ^2 ^2))/ ( ^22 ) = ( ^2 ^2)/2 = F (x, y) F ( x, y) = F (x, y) = FFree PreAlgebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators stepbystep