√100以上 (x^2+y^2)^3=4x^2y^2 181504-(x^2+y^2)^3=4x^2y^2

8x2y2/4x3y3 Final result 2x5y5 Step by step solution Step 1 y2 Simplify —— 4 Equation at the end of step 1 y2 ( ( (8 • (x2)) • ——) • x3) • y3 4 Step 2 Equation at the end of step 2 y2 Finding limit of \frac {x^2y^2} {x^3y^3} as (x,y)\to (0,0) duplicate Finding limit of x3y3x2y2

(x^2+y^2)^3=4x^2y^2-Answer (1 of 8) The above equation is general equation of second degree(ax^2–2hxy by^2–2gxfyc=0) To identify whether such equations is ellipse, parabola,hyperbola or pair of straight line By comparing the given equation with general equation of second degree weAlgebra Simplify (4x^2y^3)^2 (4x2y3)2 ( 4 x 2 y 3) 2 Use the power rule (ab)n = anbn ( a b) n = a n b n to distribute the exponent Tap for more steps Apply the product rule to 4 x 2 y 3 4 x 2 y 3 ( 4 x 2) 2 ( y 3) 2 ( 4 x 2) 2 ( y 3) 2 Apply the product rule to 4